The value of R4 is precisely becomes accountable for defining the most allowable output present.

I think Q1 and Q2 will even should replaced with the next voltage transistor. you could change it with maybe a 2N3501

No i take into consideration the large 2n3055 transistor i have improve it with another just one along with the circuit doesn,t function how is supose to operate.many thanks for fast reply.

P1 is usually a potentiometer that controls the peak output voltage, though P2 is useful for setting the minimal output voltage from the power offer.

Spehro 'speff' PefhanySpehro 'speff' Pefhany 412k2222 gold badges348348 silver badges925925 bronze badges \$\endgroup\$ 2 \$\begingroup\$ exciting sections. I like that word, boutique, to explain Linear pieces.

By the way you can also experiment with the subsequent simple strategy 1st, listed here you can easily switch the BJTs with here mosfets:

D4 is no longer significant and may be anything within the array of 1V to 4V and adjustable. As Vout attempts to exceed Q5 base/emitter voltage +0.

C4 is normally 10uF, and C10 is 1uF. Take note that diode D9 will be to discharge any substantial capacitance from the load backward to circumvent the regulator from getting reverse-biased when the enter goes small. Adjustable Voltage Regulator

I believe you'll want to validate your 2N3005 connections or its top quality..there might be a little something Incorrect around this machine inside your circuit.

Honorable Swagatam, I would like to get to the point without the need of puzzling you an excessive amount. I'm the main circuit you may have released in the following paragraphs.

How ever if this is simply not recommended I'd personally ask for you to definitely be sure to counsel an appropriate circuit for my objective.

I do think that is a should simply because also if you don't mention it, a linear regulator would dissipate approximately 70W, give or choose some. and that is an terrible great deal. Curiosity: how comes you've got this forty~50Vdc? What is your software? \$\endgroup\$

The above designs have been assessed and simplified with simpler outcomes by Mr. Nuno. The revised and simplified style may be seen in the following diagram:

Di, how can R2 melt away when R1 is existing in sequence While using the positive offer…Verify your circuit you might have accomplished a thing incorrect.